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编程小窍门:15 个提高效率的 Python 编程技巧

2021年11月25日5790百度已收录

作者:George Seif

英文原文:

编程小窍门:15 个提高效率的 Python 编程技巧  Python开发技巧 第1张

1. 交换值x, y = 1, 2print(x, y)x, y = y, xprint(x, y)2. 字符串列表合并为一个字符串sentence_list = ["my", "name", "is", "George"]sentence_string = " ".join(sentence_list)print(sentence_string)3. 将字符串拆分为子字符串列表sentence_string = "my name is George"sentence_string.split()print(sentence_string)4. 通过数字填充初始化列表[0]*1000 # List of 1000 zeros [8.2]*1000 # List of 1000 8.2's5. 字典合并x = {'a': 1, 'b': 2}y = {'b': 3, 'c': 4}z = {**x, **y}6. 反转字符串name = "George"name[::-1]7. 从函数返回多个值def get_a_string(): a = "George" b = "is" c = "cool" return a, b, csentence = get_a_string()(a, b, c) = sentence8. 列表解析式a = [1, 2, 3]b = [num*2 for num in a] # Create a new list by multiplying each element in a by 29. 遍历字典m = {'a': 1, 'b': 2, 'c': 3, 'd': 4} for key, value in m.items(): print('{0}: {1}'.format(key, value))10. 同时遍历列表的索引和值m = ['a', 'b', 'c', 'd']for index, value in enumerate(m): print('{0}: {1}'.format(index, value))11. 初始化空容器a_list = list()a_dict = dict()a_map = map()a_set = set()12. 删除字符串两端的无用字符name = " George "name_2 = "George///"name.strip() # prints "George"name_2.strip("/") # prints "George"13. 列表中出现最多的元素test = [1, 2, 3, 4, 2, 2, 3, 1, 4, 4, 4]print(max(set(test), key = test.count))14. 检查对象的内存使用情况import sysx = 1print(sys.getsizeof(x))15. 将 dict 转换为 XMLfrom xml.etree.ElementTree import Elementdef dict_to_xml(tag, d): ''' Turn a simple dict of key/value pairs into XML ''' elem = Element(tag) for key, val in d.items(): child = Element(key) child.text = str(val) elem.append(child) return elem

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